How to show only next line after the matched one?

grep -A1 'blah' logfile

Thanks to this command for every line that has 'blah' in it, I get the output of the line that contains 'blah' and the next line that follows in the logfile. It might be a simple one but I can't find a way to omit the line that has 'blah' and only show next line in the output.

you can try with awk:

awk '/blah/{getline; print}' logfile

If you want to stick to grep:

grep -A1 'blah' logfile | grep -v "blah"

or alternatively with sed:

sed -n '/blah/{n;p;}' logfile

Piping is your friend...

Use grep -A1 to show the next line after a match, then pipe the result to tail and only grab 1 line,

cat logs/info.log | grep "term" -A1 | tail -n 1