How to round up integer division and have int result in Java? [duplicate]

I just wrote a tiny method to count the number of pages for cell phone SMS. I didn't have the option to round up using Math.ceil, and honestly it seems to be very ugly.

Here is my code:

public class Main {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
   String message = "today we stumbled upon a huge performance leak while optimizing a raycasting algorithm. Much to our surprise, the Math.floor() method took almost half of the calculation time: 3 floor operations took the same amount of time as one trilinear interpolation. Since we could not belive that the floor-method could produce such a enourmous overhead, we wrote a small test program that reproduce";

   System.out.printf("COunt is %d ",(int)messagePageCount(message));



}

public static double messagePageCount(String message){
    if(message.trim().isEmpty() || message.trim().length() == 0){
        return 0;
    } else{
        if(message.length() <= 160){
            return 1;
        } else {
            return Math.ceil((double)message.length()/153);
        }
    }
}

I don't really like this piece of code and I'm looking for a more elegant way of doing this. With this, I'm expecting 3 and not 3.0000000. Any ideas?

Solution 1:

Use Math.ceil() and cast the result to int:

This is still faster than to avoid doubles by using abs().
The result is correct when working with negatives, because -0.999 will be rounded UP to 0

Example:

(int) Math.ceil((double)divident / divisor);

Solution 2:

To round up an integer division you can use

import static java.lang.Math.abs;

public static long roundUp(long num, long divisor) {
    int sign = (num > 0 ? 1 : -1) * (divisor > 0 ? 1 : -1);
    return sign * (abs(num) + abs(divisor) - 1) / abs(divisor);
}

or if both numbers are positive

public static long roundUp(long num, long divisor) {
    return (num + divisor - 1) / divisor;
}

Solution 3:

Another one-liner that is not too complicated:

private int countNumberOfPages(int numberOfObjects, int pageSize) {
    return numberOfObjects / pageSize + (numberOfObjects % pageSize == 0 ? 0 : 1);
}

Could use long instead of int; just change the parameter types and return type.

Solution 4:

Google's Guava library handles this in the IntMath class:

IntMath.divide(numerator, divisor, RoundingMode.CEILING);

Unlike many answers here, it handles negative numbers. It also throws an appropriate exception when attempting to divide by zero.

Solution 5:

(message.length() + 152) / 153

This will give a "rounded up" integer.