Omitting the first line from any Linux command output

linux

I have a requirement where i'd like to omit the 1st line from the output of ls -latr "some path" Since I need to remove total 136 from the below output

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So I wrote ls -latr /home/kjatin1/DT_901_linux//autoInclude/system | tail -q which excluded the 1st line, but when the folder is empty it does not omit it. Please tell me how to omit 1st line in any linux command output

Solution 1:

The tail program can do this:

ls -lart | tail -n +2

The -n +2 means “start passing through on the second line of output”.

Solution 2:

Pipe it to awk:

awk '{if(NR>1)print}'

or sed

sed -n '1!p'

Solution 3:

ls -lart | tail -n +2 #argument means starting with line 2

Solution 4:

This is a quick hacky way: ls -lart | grep -v ^total.

Basically, remove any lines that start with "total", which in ls output should only be the first line.

A more general way (for anything):

ls -lart | sed "1 d"

sed "1 d" means only print everything but first line.

Solution 5:

You can use awk command:

For command output use pipe: | awk 'NR>1'

For output of file: awk 'NR>1' file.csv