How to cast Expression<Func<T, DateTime>> to Expression<Func<T, object>>
You can't just cast between them, as they're not the same kind of thing. However, you can effectively add a conversion within the expression tree:
using System;
using System.Linq.Expressions;
class Test
{
// This is the method you want, I think
static Expression<Func<TInput,object>> AddBox<TInput, TOutput>
(Expression<Func<TInput, TOutput>> expression)
{
// Add the boxing operation, but get a weakly typed expression
Expression converted = Expression.Convert
(expression.Body, typeof(object));
// Use Expression.Lambda to get back to strong typing
return Expression.Lambda<Func<TInput,object>>
(converted, expression.Parameters);
}
// Just a simple demo
static void Main()
{
Expression<Func<string, DateTime>> x = text => DateTime.Now;
var y = AddBox(x);
object dt = y.Compile()("hi");
Console.WriteLine(dt);
}
}
The answers from Rob and Jon Skeet have one problem.
You get something like x => Convert(x.PropertyName)
, but often for instance for ASP.NET MVC you want an expression like this x => x.PropertyName
So Expression.Convert
is "polluting" the expression for some cases.
Solution:
public static class LambdaExpressionExtensions
{
public static Expression<Func<TInput, object>> ToUntypedPropertyExpression<TInput, TOutput> (this Expression<Func<TInput, TOutput>> expression)
{
var memberName = ((MemberExpression)expression.Body).Member.Name;
var param = Expression.Parameter(typeof(TInput));
var field = Expression.Property(param, memberName);
return Expression.Lambda<Func<TInput, object>>(field, param);
}
}
Usage:
Expression<Func<T, DateTime>> expression = ...;
Expression<Func<T, object>> expr = expression.ToUntypedPropertyExpression();
Based on the code from Jon (thanks btw) you can take it one step further for complete flexibility:
public static Expression<Func<TModel, TToProperty>> Cast<TModel, TFromProperty, TToProperty>(Expression<Func<TModel, TFromProperty>> expression)
{
Expression converted = Expression.Convert(expression.Body, typeof(TToProperty));
return Expression.Lambda<Func<TModel, TToProperty>>(converted, expression.Parameters);
}