GetHashCode() on byte[] array
Arrays in .NET don't override Equals
or GetHashCode
, so the value you'll get is basically based on reference equality (i.e. the default implementation in Object
) - for value equality you'll need to roll your own code (or find some from a third party). You may want to implement IEqualityComparer<byte[]>
if you're trying to use byte arrays as keys in a dictionary etc.
EDIT: Here's a reusable array equality comparer which should be fine so long as the array element handles equality appropriately. Note that you mustn't mutate the array after using it as a key in a dictionary, otherwise you won't be able to find it again - even with the same reference.
using System;
using System.Collections.Generic;
public sealed class ArrayEqualityComparer<T> : IEqualityComparer<T[]>
{
// You could make this a per-instance field with a constructor parameter
private static readonly EqualityComparer<T> elementComparer
= EqualityComparer<T>.Default;
public bool Equals(T[] first, T[] second)
{
if (first == second)
{
return true;
}
if (first == null || second == null)
{
return false;
}
if (first.Length != second.Length)
{
return false;
}
for (int i = 0; i < first.Length; i++)
{
if (!elementComparer.Equals(first[i], second[i]))
{
return false;
}
}
return true;
}
public int GetHashCode(T[] array)
{
unchecked
{
if (array == null)
{
return 0;
}
int hash = 17;
foreach (T element in array)
{
hash = hash * 31 + elementComparer.GetHashCode(element);
}
return hash;
}
}
}
class Test
{
static void Main()
{
byte[] x = { 1, 2, 3 };
byte[] y = { 1, 2, 3 };
byte[] z = { 4, 5, 6 };
var comparer = new ArrayEqualityComparer<byte>();
Console.WriteLine(comparer.GetHashCode(x));
Console.WriteLine(comparer.GetHashCode(y));
Console.WriteLine(comparer.GetHashCode(z));
Console.WriteLine(comparer.Equals(x, y));
Console.WriteLine(comparer.Equals(x, z));
}
}
Like other non-primitive built-in types, it just returns something arbitrary. It definitely doesn't try to hash the contents of the array. See this answer.
byte[]
inherits GetHashCode()
from object
, it doesn't override it. So what you get is basically object
's implementation.
Simple solution
public static int GetHashFromBytes(byte[] bytes)
{
return new BigInteger(bytes).GetHashCode();
}
If it's not the same instance, it will return different hashes. I'm guessing it is based on the memory address where it is stored somehow.