Using a Python subprocess call to invoke a Python script

If 'somescript.py' isn't something you could normally execute directly from the command line (I.e., $: somescript.py works), then you can't call it directly using call.

Remember that the way Popen works is that the first argument is the program that it executes, and the rest are the arguments passed to that program. In this case, the program is actually python, not your script. So the following will work as you expect:

subprocess.call(['python', 'somescript.py', somescript_arg1, somescript_val1,...]).

This correctly calls the Python interpreter and tells it to execute your script with the given arguments.

Note that this is different from the above suggestion:

subprocess.call(['python somescript.py'])

That will try to execute the program called python somscript.py, which clearly doesn't exist.

call('python somescript.py', shell=True)

Will also work, but using strings as input to call is not cross platform, is dangerous if you aren't the one building the string, and should generally be avoided if at all possible.

Windows? Unix?

Unix will need a shebang and exec attribute to work:

#!/usr/bin/env python

as the first line of script and:

chmod u+x script.py

at command-line or

call('python script.py'.split())

as mentioned previously.

Windows should work if you add the shell=True parameter to the "call" call.

Check out this.

from subprocess import call 
with open('directory_of_logfile/logfile.txt', 'w') as f:
   call(['python', 'directory_of_called_python_file/called_python_file.py'], stdout=f)

subprocess.call expects the same arguments as subprocess.Popen - that is a list of strings (the argv in C) rather than a single string.

It's quite possible that your child process attempted to run "s" with the parameters "o", "m", "e", ...