How get value of promise? [duplicate]
I'm looking at this example from Angular's docs for $q
but I think this probably applies to promises in general. The example below is copied verbatim from their docs with their comment included:
promiseB = promiseA.then(function(result) {
return result + 1;
});
// promiseB will be resolved immediately after promiseA is resolved and its value
// will be the result of promiseA incremented by 1
I'm not clear how this works. If I can call .then()
on the result of the first .then()
, chaining them, which I know I can, then promiseB
is a promise object, of type Object
. It is not a Number
. So what do they mean by "its value will be the result of promiseA incremented by 1"?
Am I supposed to access that as promiseB.value
or something like that? How can the success callback return a promise AND return "result + 1"? I'm missing something.
Solution 1:
promiseA
's then
function returns a new promise (promiseB
) that is immediately resolved after promiseA
is resolved, its value is the value of the what is returned from the success function within promiseA
.
In this case promiseA
is resolved with a value - result
and then immediately resolves promiseB
with the value of result + 1
.
Accessing the value of promiseB
is done in the same way we accessed the result of promiseA
.
promiseB.then(function(result) {
// here you can use the result of promiseB
});
Edit December 2019: async
/await
is now standard in JS, which allows an alternative syntax to the approach described above. You can now write:
let result = await functionThatReturnsPromiseA();
result = result + 1;
Now there is no promiseB, because we've unwrapped the result from promiseA using await
, and you can work with it directly.
However, await
can only be used inside an async
function. So to zoom out slightly, the above would have to be contained like so:
async function doSomething() {
let result = await functionThatReturnsPromiseA();
return result + 1;
}
Solution 2:
When a promise is resolved/rejected, it will call its success/error handler:
var promiseB = promiseA.then(function(result) {
// do something with result
});
The then
method also returns a promise: promiseB, which will be resolved/rejected depending on the return value from the success/error handler from promiseA.
There are three possible values that promiseA's success/error handlers can return that will affect promiseB's outcome:
1. Return nothing --> PromiseB is resolved immediately,
and undefined is passed to the success handler of promiseB
2. Return a value --> PromiseB is resolved immediately,
and the value is passed to the success handler of promiseB
3. Return a promise --> When resolved, promiseB will be resolved.
When rejected, promiseB will be rejected. The value passed to
the promiseB's then handler will be the result of the promise
Armed with this understanding, you can make sense of the following:
promiseB = promiseA.then(function(result) {
return result + 1;
});
The then call returns promiseB immediately. When promiseA is resolved, it will pass the result to promiseA's success handler. Since the return value is promiseA's result + 1, the success handler is returning a value (option 2 above), so promiseB will resolve immediately, and promiseB's success handler will be passed promiseA's result + 1.
Solution 3:
.then
function of promiseB receives what is returned from .then
function of promiseA.
here promiseA is returning is a number, which will be available as number
parameter in success function of promiseB. which will then be incremented by 1