Easiest way to filter a list

I have an API that returns store availability for an Item, The product should be considered Ready To Purchase if any of the stores return 200, and Not Ready to every other status codes (Including 404).

{
  "status": 200,
  "sku": "svk__21w",
  "store_data": [
    {
      "status": 404,
      "reason": "no product found, or product is not available, or not in inventory"
    },
    {
      "status": 404,
      "reason": "no product found, or product is not available, or not in inventory"
    },
    {
      "status": 404,
      "reason": "no product found, or product is not available, or not in inventory"
    }
  ]
}

Now, In my code, To check If this product is indeed Ready To Purchase or not, I use a for loop:

is_product_available = False
for store in data['store_data']:
   if 'data' in store and store['status'] == 200:
        print("Product state is ready to purchase")

        is_product_available = True
   else:
        print("Product state is not ready to purchase")

Which works, But I think it's just bad design, In the future, With more stores opening..

What I want:

• A better way to check if any of the stores have data and their code is 200 and if so, the product is Ready To Purchase.

Example of a Ready To Purchase product:

store_data: 
   store_1: 404
   store_2: 404
   store_3 200

Example of a Not Ready To Purchase product:

store_data: 
   store_1: 404
   store_2: 404
   store_3 404

Solution 1:

You can use the any function

is_product_available = any([store['status'] == 200 for store in data['store_data']])

Solution 2:

You can use function any and a generator expression to do that most efficiently like

is_ready = any(d.get("status", 0) == 200 for d in data['store_data'])

this will return True once it found the first match that is true. So if there are 10_000 entries and the first is already 200, it will only have to check that.