Find if array of arrays contains more than 1 nan element?

I want to find if conf_int_arr has more than 1 [nan, nan] array, how can i do that?

conf_int_arr = [array([nan, nan]),
 array([39.49, 57.08]),
 array([nan, nan]),
 array([nan, nan])]

I searched the solution but this not works.

np.where(conf_int_arr != conf_int_arr.round())

You can simply convert your list to a numpy array and then count the rows which only contain nan values:

import numpy as np

conf_int_arr = [np.array([np.nan, np.nan]),
 np.array([39.49, 57.08]),
 np.array([np.nan, np.nan]),
 np.array([np.nan, np.nan])]

conf_int_arr = np.array(conf_int_arr)
result = np.isnan(conf_int_arr).all(axis=1).sum()

print(result)

Output:

3

I am not sure if this is the most efficient way to do it but it works.

import numpy as np


conf_int_arr = [
    np.array([np.nan, np.nan]),
    np.array([39.49, 57.08]),
    np.array([np.nan, np.nan]),
    np.array([np.nan, np.nan]),
]
nan_array = np.array([np.nan, np.nan])
print(np.sum([np.array_equal(each_array, nan_array, equal_nan=True) for each_array in conf_int_arr]))