Delete the rows which have NaN in every cells in python

I have a data called data .

The problem with this data is that a lot of rows have NaN I want to delete every rows which have NaN in every cells except time. For example, I wnat to delete the row with time 2021-12-24 01:00:20 and the row with time 2021-12-24 01:00:30 in this case. The import thing is that I don't want to delete the rows with only a few NaN. I wnat to delete the rows which have every cells NaN except time. How can I do?

You can do it explicitly if you need to tweak it, or just using the function that pandas offers for this:

from pandas import DataFrame, to_datetime

data = [
     ['2022-01-01 00:00', 1, 2, 3],
     ['2022-01-02 00:00', None, 2, 3],
     ['2022-01-03 00:00', None, None, None],
     ['2022-01-04 00:00', 1, 2, None],
     ['2022-01-05 00:00', None, None, None],
]
df = DataFrame(data, columns=['time', 'x', 'y', 'z'])
df['time'] = to_datetime(df['time'])

# explicitly select all the columns after the first, check if values are nan, 
# then get the indices for all rows where every cell is true - drop those rows
one = df.drop(df[df.iloc[:, 1:].isnull().all(axis=1)].index)
print(one)

# but pandas allows you to do it in one go as long as `time` is never nan
two = df.dropna(thresh=len(df.columns)-1)
print(two)