How to print a specific character from a string in C

I'm recently practicing looping. I learned how to print: for example home to h ho hom home. by using

#include <stdio.h>
#include <string.h>

int main (){
    char s[100];
    
    printf("Input string = ");
    scanf("%[^\n]", s);
    
    for (int i=1; i<=strlen(s); i++){
        for(int j = 0; j<i; j++)
        printf("%c", s[j]);
        printf("\n");
    }

    return 0;

How can i reverse it so it can be home hom ho h instead? thank you.

It is easy to do. For example

for ( size_t i = strlen( s ); i != 0; i-- )
{
    for ( size_t j = 0; j < i; j++ )
    { 
        putchar( s[j] );
    }
    putchar( '\n' );
}

Another way is the following

for ( size_t i = strlen( s ); i != 0; i-- )
{
    printf( ".*s\n", ( int )i, s );
}

provided that an object of the type int is able to store the length of the passed string.

Here is a demonstration program.

#include <stdio.h>
#include <string.h>

int main( void )
{
    const char *s = "home";

    for (size_t i = strlen( s ); i != 0; i--)
    {
        printf( "%.*s\n", ( int )i, s );
    }
}

The program output is

home
hom
ho
h

You could loop over the string using putc, but it might also be helpful to understand the destructive approach that shortens the string and uses %s to print strings. eg:

#include <stdio.h>
#include <string.h>

int
main(int argc, char **argv)
{
    char *s = argc > 1 ? argv[1] : strdup("home");
    for( char *e = s + strlen(s); e > s; e -= 1 ){
        *e = '\0';
        printf("%s\n", s);
    }
    return 0;
}

Note that this approach is destructive. When complete, the string is null. As an exercise, it might be helpful to fix that.