HHow to merge different arrays with similar object property?

I have two different arrays as below.

1st Array : arr1
0: {ID: '1', Name: 'Suyog Patil', IsSelected: false, Location: 'Mumbai'}
1: {ID: '2', Name: 'John Doe', IsSelected: false, Location: 'London'}
2: {ID: '3', Name: 'Santosh Sarnobat', IsSelected: false, Location: 'Panvel'}
3: {ID: '4', Name: 'Sai Panhalkar', IsSelected: false, Location: 'Belapur'}

2nd Array : arr2
0: {ID: '1', IsSelected: true}
1: {ID: '3', IsSelected: true}

Now, I want the replace the properties of array1 with properties of array2 where ID property is same.
So, the final array would look like (I need to get below output)

0: {ID: '1', Name: 'Suyog Patil', IsSelected: true, Location: 'Mumbai'}      //Replaced value
1: {ID: '2', Name: 'John Doe', IsSelected: false, Location: 'London'}
2: {ID: '3', Name: 'Santosh Sarnobat', IsSelected: true, Location: 'Panvel'} //Replaced value
3: {ID: '4', Name: 'Sai Panhalkar', IsSelected: false, Location: 'Belapur'}

Here, you can see, IsSelected property is replaced to true where ID equals 1 & 3.

This is what I have tried so far, but not able to achieve.

arr3 = [].concat(arr1, arr2);

But, it gives 6 results, it literally concats as the function says

Solution 1:

Here is a non-jQuery version using much simplified code

const arr1 = [
  {"ID":"1","Name":"Suyog Patil","IsSelected":false,"Location":"Mumbai"},
  {"ID":"2","Name":"John Doe","IsSelected":false,"Location":"London"},
  {"ID":"3","Name":"Santosh Sarnobat","IsSelected":false,"Location":"Panvel"},
  {"ID":"4","Name":"Sai Panhalkar","IsSelected":false,"Location":"Belapur"}
],
arr2 = [{"ID":"1","IsSelected":true}, {"ID":"3","IsSelected":true}],
arr3 = arr1.map(item => ({...item,IsSelected: arr2.find(({ID}) => ID === item.ID) || false}))


console.log("-----ARRAY 3-----");
console.log(arr3);

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