how to filter based on two values from the array of array
Solution 1:
You might wanna use Array.filter() and also in your case you should check every element from that array which should match your criteria.
const input = [{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bae01b4ccf060b329441ef"
],
"_id": "61bae0394ccf060b329441fb",
},
{
"messages": [],
"participants": [
"61bae1014ccf060b3294420e",
"61bae01b4ccf060b329441ef"
],
"_id": "61bb230c4ccf060b3294421c"
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bc33a84ccf060b32944354"
],
"_id": "61d476dff651471663a72971",
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61e54b82eab592e7fef65656"
],
"_id": "61e54ba3eab592e7fef6567a",
}
];
const filterByParticipants = ["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"];
const output = input.filter(el => el.participants.every(el => filterByParticipants.includes(el)));
console.log(output);Solution 2:
You need to use filter() method of Array Object, to filter it based on certain conditions.
You can then use every() method of participants array, to check if every participant is present in the object.
let obj=[{messages:[],participants:["61badffe4ccf060b329441e0","61bae01b4ccf060b329441ef"],_id:"61bae0394ccf060b329441fb"},{messages:[],participants:["61bae1014ccf060b3294420e","61bae01b4ccf060b329441ef"],_id:"61bb230c4ccf060b3294421c"},{messages:[],participants:["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"],_id:"61d476dff651471663a72971"},{messages:[],participants:["61badffe4ccf060b329441e0","61e54b82eab592e7fef65656"],_id:"61e54ba3eab592e7fef6567a"}];
let participants =["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"];
let res = obj.filter((o)=>{
let oParticipants = o.participants;
let out = participants.every(p => oParticipants.includes(p))
return out;
});
console.log(res)