Bash: simple math operations on fractional numbers [duplicate]
I do something like the following in a Makefile:
echo "0.1 + 0.1" | bc
(in the real file the numbers are dynamic, of course)
It prints .2 but I want it to print 0.2.
I would like to do this without resorting to sed but I can't seem to find how to get bc to print the zero. Or is bc just not able to do this?
You can also resort to awk to format:
echo "0.1 + 0.1" | bc | awk '{printf "%f", $0}'
or with awk itself doing the math:
echo "0.1 0.1" | awk '{printf "%f", $1 + $2}'
This might work for you:
echo "x=0.1 + 0.1; if(x<1) print 0; x" | bc