How to pass an "int" value into any bits of a "char" array? [closed]

int x = 10;
char denemem[13]="|          |";

How can I get the output shown below by writing a code in C programming language? or, more precisely, how can I pass int into the any place (any bits) of a char array I want?

|    10    |

Thank you for all of your help and efforts in advance!

Assuming you want a fixed width, printf can do that directly, as long as you want left or right justified:

printf("|%10d|", x);    // right justified
printf("|%-10d|", x);   // left justified

Unfortunately, if you want the number centered in a field, that is much harder to do. You need to figure out how wide the number is and then pad:

int width = snprintf(0, 0, "%d", x);
if (width <= 10) {
    width += (10-width)/2;
    printf("|%*d%*s|", width, x, 10-width, "");
} else {
    // number is too wide for the field -- do something else