How to parse 127.0.0.1:1234 [closed]
I am trying to parse 127.0.0.1:1234 with urlparse
urlparse('127.0.0.1:1234')
and it is giving me this result
ParseResult(scheme='127.0.0.1', netloc='', path='1234', params='', query='', fragment='')
I want 127.0.0.1 in netloc field.
How to do that?
Solution 1:
You need to add a scheme before the URL, http or https
URL = 'http://127.0.0.1:1234'
# Here http is the scheme and 127.0.0.1 is the netloc
parsed_obj = urlparse('http://127.0.0.1:1234')
print(parsed_obj)
# ParseResult(scheme='http', netloc='127.0.0.1:1234', path='', params='', query='', fragment='')