Is it possilbe to get a pointer to a generic lambda explicit instantiation?

Solution 1:

Yes, and you can omit the template arguments if they can be deduced from the type being initialized (or the result type of a cast) but since the lambda isn’t mutable the member function is const and so must be the pointer-to-member.

Solution 2:

Is it possible to get a (member) function pointer to a specific instantiation of a generic lambda?

Lambda's operator() is const-qualified by default, you need to add const to the member function pointer type

void (generic_type::*pf3)(int) const = &generic_type::operator();

And since pf3 is a member function pointer, please note that it need a specific lambda object and uses .* or ->* to invoke.

(generic_template.*pf3)(42);

Demo