Why doesn't grepl(":digit:", "1") evaluate TRUE? [duplicate]

I'm having some problems matching a pattern with a string of text in R.

I'm trying to get TRUE with grepl when the text is something like "lettersornumbersorspaces y lettersornumbersorspaces".

I'm using the following regex:

([:alnum:]|[:blank:])+[:blank:][yY][:blank:]([:alnum:]|[:blank:])+

When using the regex as follows to obtain the "address" it works at expected.

regex <- "([:alnum:]|[:blank:])+[:blank:][yY][:blank:]([:alnum:]|[:blank:])+"
address <- str_extract(fulltext, regex)

I see that address is the text that I need. Now, if I want to use grepl to get a TRUE as follows:

grepl("([:alnum:]|[:blank:])+[:blank:][yY][:blank:]([:alnum:]|[:blank:])+", address,ignore.case = TRUE)

FALSE is returned. How is this possible? I'm using the same regex to get TRUE. I have tried modifications to the grepl parameters, but non of them is related to this.

An example of text is: "26 de Marzo y Pareyra de la Luz"

Thanks!!

Solution 1:

Although stringr ICU regex engines supports bare POSIX character classes in the pattern, in base R regex flavors (both PCRE (perl=TRUE) and TRE), POSIX character classes must be inside bracket expressions. [:alnum:] -> [[:alnum:]].

x <- c("AZaz09 y AZaz09", "ĄŻaz09 y AZŁł09", "26 de Marzo y Pareyra de la Luz")
grepl("[[:alnum:][:blank:]]+[[:blank:]][yY][[:blank:]][[:alnum:][:blank:]]+", x)
## => [1] TRUE TRUE TRUE
grepl("[[:alnum:][:blank:]]+[[:blank:]][yY][[:blank:]][[:alnum:][:blank:]]+", x, perl=TRUE)
## => [1] TRUE TRUE TRUE

See the online demo

When you use [:alnum:] alone, it is a simple bracket expression that matches a single character, a :, a, l, n, u, m.

Pattern details:

• [[:alnum:][:blank:]]+ - 1+ alphanumeric or horizontal whitespace symbols
• [[:blank:]] - 1 horizontal whitespace symbols
• [yY] - either y or Y
• [[:blank:]] - 1 horizontal whitespace symbols
• [[:alnum:][:blank:]]+ - 1+ alphanumeric or horizontal whitespace symbols