Is there an easier way to get the current time in hh:mm:ss format?

I tried to print the current time in the usual format of hh:mm:ss however I get the full date format instead. I need the answer to be in string or int, so it is easier to deal with. I was thinking of adding it to a log file so that I can make it easier to track my program.

#include <iostream>
#include <chrono>
#include <ctime>    

int main()
{
    auto curr_time = std::chrono::system_clock::now();
    std::time_t pcurr_time = std::chrono::system_clock::to_time_t(curr_time);
    std::cout << "current time" << std::ctime(&pcurr_time)<<"\n";
}

I do want a little tip to help me do so.

Solution 1:

The following example displays the time in the "HH:MM:SS" format (requires at least c++11 - tested with clang):

#include <iostream>
#include <iomanip>
#include <chrono>
#include <ctime>

int main()
{
    std::time_t t = std::chrono::system_clock::to_time_t(std::chrono::system_clock::now());
    std::tm ltime;
    localtime_r(&t, &ltime);
    std::cout << std::put_time(&ltime, "%H:%M:%S") << std::endl;
}

Compiling and running:

$ clang++ -std=c++11 so.cpp
$ ./a.out
13:44:23
$

Solution 2:

Using std::chrono and std::format:

• You can just pass a time_point and format it according to a format specification. In the example below %T is equivalent to %H:%M:%S (hours in 24-hour clock, and minutes and seconds using 2 digits).
• If you don't want to print out microseconds, you can floor the current time.

Note std::format requires C++20.

#include <chrono>
#include <format>
#include <iostream>  // cout

int main(int argc, const char* argv[])
{
    namespace ch = std::chrono;
    std::cout << std::format("{:%T}", ch::floor<ch::seconds>(ch::system_clock::now()));
}