Regex: Find all values between specific words [duplicate]

var ss= "<pre>aaaa\nbbb\nccc</pre>ddd";
var arr= ss.match( /<pre.*?<\/pre>/gm );
alert(arr);     // null

I'd want the PRE block be picked up, even though it spans over newline characters. I thought the 'm' flag does it. Does not.

Found the answer here before posting. SInce I thought I knew JavaScript (read three books, worked hours) and there wasn't an existing solution at SO, I'll dare to post anyways. throw stones here

So the solution is:

var ss= "<pre>aaaa\nbbb\nccc</pre>ddd";
var arr= ss.match( /<pre[\s\S]*?<\/pre>/gm );
alert(arr);     // <pre>...</pre> :)

Does anyone have a less cryptic way?

Edit: this is a duplicate but since it's harder to find than mine, I don't remove.

It proposes [^] as a "multiline dot". What I still don't understand is why [.\n] does not work. Guess this is one of the sad parts of JavaScript..

Solution 1:

DON'T use (.|[\r\n]) instead of . for multiline matching.

DO use [\s\S] instead of . for multiline matching

Also, avoid greediness where not needed by using *? or +? quantifier instead of * or +. This can have a huge performance impact.

See the benchmark I have made: http://jsperf.com/javascript-multiline-regexp-workarounds

Using [^]: fastest
Using [\s\S]: 0.83% slower
Using (.|\r|\n): 96% slower
Using (.|[\r\n]): 96% slower

NB: You can also use [^] but it is deprecated in the below comment.

Solution 2:

[.\n] does not work because . has no special meaning inside of [], it just means a literal .. (.|\n) would be a way to specify "any character, including a newline". If you want to match all newlines, you would need to add \r as well to include Windows and classic Mac OS style line endings: (.|[\r\n]).

That turns out to be somewhat cumbersome, as well as slow, (see KrisWebDev's answer for details), so a better approach would be to match all whitespace characters and all non-whitespace characters, with [\s\S], which will match everything, and is faster and simpler.

In general, you shouldn't try to use a regexp to match the actual HTML tags. See, for instance, these questions for more information on why.

Instead, try actually searching the DOM for the tag you need (using jQuery makes this easier, but you can always do document.getElementsByTagName("pre") with the standard DOM), and then search the text content of those results with a regexp if you need to match against the contents.

Solution 3:

You do not specify your environment and version of Javascript (ECMAscript), and I realise this post was from 2009, but just for completeness, with the release of ECMA2018 we can now use the s flag to cause . to match '\n', see https://stackoverflow.com/a/36006948/141801

Thus:

let s = 'I am a string\nover several\nlines.';
console.log('String: "' + s + '".');

let r = /string.*several.*lines/s; // Note 's' modifier
console.log('Match? ' + r.test(s); // 'test' returns true

This is a recent addition and will not work in many current environments, for example Node v8.7.0 does not seem to recognise it, but it works in Chromium, and I'm using it in a Typescript test I'm writing and presumably it will become more mainstream as time goes by.

Solution 4:

[.\n] doesn't work, because dot in [] (by regex definition; not javascript only) means the dot-character. You can use (.|\n) (or (.|[\n\r])) instead.

Solution 5:

I have tested it (Chrome) and it's working for me (both [^] and [^\0]), by changing the dot (.) with either [^\0] or [^] , because dot doesn't match line break (See here: http://www.regular-expressions.info/dot.html).

var ss= "<pre>aaaa\nbbb\nccc</pre>ddd";
var arr= ss.match( /<pre[^\0]*?<\/pre>/gm );
alert(arr);     //Working