Use array element as structure field or property in golang [duplicate]

Solution 1:

Most code shouldn't need this sort of dynamic lookup. It's inefficient compared to direct access (the compiler knows the offset of the X field in a Vertex structure, it can compile v.X to a single machine instruction, whereas a dynamic lookup will need some sort of hash table implementation or similar). It's also inhibits static typing: the compiler has no way to check that you're not trying to access unknown fields dynamically, and it can't know what the resulting type should be.

But... the language provides a reflect module for the rare times you need this.

package main

import "fmt"
import "reflect"

type Vertex struct {
    X int
    Y int
}

func main() {
    v := Vertex{1, 2}
    fmt.Println(getField(&v, "X"))
}

func getField(v *Vertex, field string) int {
    r := reflect.ValueOf(v)
    f := reflect.Indirect(r).FieldByName(field)
    return int(f.Int())
}

There's no error checking here, so you'll get a panic if you ask for a field that doesn't exist, or the field isn't of type int. Check the documentation for reflect for more details.

Solution 2:

You now have the project oleiade/reflections which allows you to get/set fields on struct value or pointers.
It makes using the reflect package less tricky.

s := MyStruct {
    FirstField: "first value",
    SecondField: 2,
    ThirdField: "third value",
}

fieldsToExtract := []string{"FirstField", "ThirdField"}

for _, fieldName := range fieldsToExtract {
    value, err := reflections.GetField(s, fieldName)
    DoWhatEverWithThatValue(value)
}


// In order to be able to set the structure's values,
// a pointer to it has to be passed to it.
_ := reflections.SetField(&s, "FirstField", "new value")

// If you try to set a field's value using the wrong type,
// an error will be returned
err := reflection.SetField(&s, "FirstField", 123)  // err != nil