Validating parameters to a Bash script

Solution 1:

#!/bin/sh
die () {
    echo >&2 "$@"
    exit 1
}

[ "$#" -eq 1 ] || die "1 argument required, $# provided"
echo $1 | grep -E -q '^[0-9]+$' || die "Numeric argument required, $1 provided"

while read dir 
do
    [ -d "$dir" ] || die "Directory $dir does not exist"
    rm -rf "$dir"
done <<EOF
~/myfolder1/$1/anotherfolder 
~/myfolder2/$1/yetanotherfolder 
~/myfolder3/$1/thisisafolder
EOF

edit: I missed the part about checking if the directories exist at first, so I added that in, completing the script. Also, have addressed issues raised in comments; fixed the regular expression, switched from == to eq.

This should be a portable, POSIX compliant script as far as I can tell; it doesn't use any bashisms, which is actually important because /bin/sh on Ubuntu is actually dash these days, not bash.

Solution 2:

The sh solution by Brian Campbell, while noble and well executed, has a few problems, so I thought I'd provide my own bash solution.

The problems with the sh one:

• The tilde in ~/foo doesn't expand to your homedirectory inside heredocs. And neither when it's read by the read statement or quoted in the rm statement. Which means you'll get No such file or directory errors.
• Forking off grep and such for basic operations is daft. Especially when you're using a crappy shell to avoid the "heavy" weight of bash.
• I also noticed a few quoting issues, for instance around a parameter expansion in his echo.
• While rare, the solution cannot cope with filenames that contain newlines. (Almost no solution in sh can cope with them - which is why I almost always prefer bash, it's far more bulletproof & harder to exploit when used well).

While, yes, using /bin/sh for your hashbang means you must avoid bashisms at all costs, you can use all the bashisms you like, even on Ubuntu or whatnot when you're honest and put #!/bin/bash at the top.

So, here's a bash solution that's smaller, cleaner, more transparent, probably "faster", and more bulletproof.

[[ -d $1 && $1 != *[^0-9]* ]] || { echo "Invalid input." >&2; exit 1; }
rm -rf ~/foo/"$1"/bar ...

1. Notice the quotes around $1 in the rm statement!
2. The -d check will also fail if $1 is empty, so that's two checks in one.
3. I avoided regular expressions for a reason. If you must use =~ in bash, you should be putting the regular expression in a variable. In any case, globs like mine are always preferable and supported in far more bash versions.

Solution 3:

Not as bulletproof as the above answer, however still effective:

#!/bin/bash
if [ "$1" = "" ]
then
  echo "Usage: $0 <id number to be cleaned up>"
  exit
fi

# rm commands go here