Command line: Extract substring from output

Solution 1:

$ echo "Watermelons and cucumbers" | cut -d ' ' -f 3
cucumbers

The -d ' ' tells cut to split on spaces. -f 3 selects the third column.

You can also use awk, which does the splitting based on space already and makes the columns available as $1, $2, …

$ echo "Watermelons and cucumbers" | awk '{ print $3 }'
cucumbers

Solution 2:

I would probably use one of the options already given by @slhck but here are a few more ways of doing this:

1. Using arrays, as you would in any other language:

   $ foo=( $(SayStuff) ) 
   $ echo ${foo[2]}
   cucumbers
   

   The var=() declares an array, $(command) saves the output of the command. So, foo=( $(SayStuff) ) stores the output of SayStuff into the array foo and yuou then echo it's third element with ${foo[2]}.

2. sed

   $ SayStuff | sed 's/.* \(.*\)/\1/'
   cucumbers
   

   The sed command will substitute (s///) everything with the last word. The regex matches anything up to a space (.*) which will match everything up to the last space and then captures the last word (\(.*\). Since the word has been captures, we can refer to it as \1.

   A simpler version:

   $ SayStuff | sed 's/.* //'
   cucumbers
   

3. bash

   $ foo=$(SayStuff); echo ${foo##* } 
   cucumbers
   

   This uses bash's string manipulation abilities, see here for more details.

4. More bash

   $ SayStuff | while read a b c; do echo $c; done
   cucumbers
   

5. Perl, where of course, there are many ways to do this:

   $ SayStuff | perl -lane 'print $F[$#F]'
   cucumber
   

   The -a makes perl behave like awk, splitting lines at whitespace and saving into the array @F. We then print the last element of @F ($#F is the number of elements in @F). The -l tells perl to add a newline to each print statement, the -n that it should process STDIN line by line and -e that it should run the script given at the command line.

   $ SayStuff | perl -pe 's/.* //'
   cucumber
   

   The options were explained above, we are just deleting everything till the last space and printing (-p).

   $ perl -le 'print $ARGV[$#ARGV]' $(SayStuff)
   cucumbers
   

   Here we are passing Watermelons and cucumbers as arguments, which perl will save in the @ARG array and so, we print the last element of @ARG.

6. trickery. This one uses sed to convert spaces to newlines and then tail to print only the last line.

   $ SayStuff | sed 's/ /\n/g' | tail -n 1
   cucumbers
   

7. grep and regular expressions, using -o which prints only the matched string.

   $ SayStuff | grep -Po '\w+$' 
   cucumbers
   

8. cheating

   $ SayStuff | grep -o cucumbers
   cucumbers
   

Solution 3:

Here is some more explanation:

Usage: cut OPTION... [FILE]...

Print selected parts of lines from each FILE to standard output.

   -d, --delimiter=DELIM
          use DELIM instead of TAB for field delimiter

   -f, --fields=LIST
          select only these fields;  also print any line that contains  no
          delimiter character, unless the -s option is specified

So if you need the 3rd field and it is delimited by spaces ' ' then it is

$ echo "Watermelons and cucumbers" | cut -d ' ' -f 3  
cucumbers

If you want the LAST field you probably should use awk.
In this case it becomes:

$ echo "Watermelons and cucumbers" | awk '{ print $NF }'
cucumbers

In awk NF is the number of fields in the line so $NF means the last field in the line.