How can I make an expect script prompt for a password?

Solution 1:

Use expect's stty command like this:

# grab the password
stty -echo
send_user -- "Password for $user@$host: "
expect_user -re "(.*)\n"
send_user "\n"
stty echo
set pass $expect_out(1,string)

#... later
send -- "$pass\r"

Note that it's important to call stty -echo before calling send_user -- I'm not sure exactly why: I think it's a timing issue.

expect programmers should all read the book: Exploring Expect by Don Libes

Solution 2:

OK, merging the 2 answers above (or below or wherever they are now!):

#!/usr/bin/expect
log_user 0
set timeout 10
set userid  "XXXXX"
set pass    "XXXXXX"

### Get two arguments - (1) Host (2) Command to be executed
set host    [lindex $argv 0] 
set command [lindex $argv 1]

# grab the password
stty -echo
send_user -- "Password for $userid@$host: "
expect_user -re "(.*)\n"
send_user "\n"
stty echo
set pass $expect_out(1,string)

spawn /usr/bin/ssh -l $userid $host
match_max [expr 32 * 1024]

expect {
    -re "RSA key fingerprint" {send "yes\r"}
    timeout {puts "Host is known"}
}

expect {
     -re "username: " {send "$userid\r"} 
     -re "(P|p)assword: " {send "$pass\r"}
     -re "Warning:" {send "$pass\r"}
     -re "Connection refused" {puts "Host error -> $expect_out(buffer)";exit}
     -re "Connection closed"  {puts "Host error -> $expect_out(buffer)";exit}
     -re "no address.*" {puts "Host error -> $expect_out(buffer)";exit}

     timeout {puts "Timeout error. Is host down or unreachable?? ssh_expect";exit}
}

expect {
   -re "\[#>]$" {send "term len 0\r"}
   timeout {puts "Error reading prompt -> $expect_out(buffer)";exit}
}


expect {
   -re "\[#>]$" {send "$command\r"}

   timeout {puts "Error reading prompt -> $expect_out(buffer)";exit}
}

expect -re "\[#>]$"
set output $expect_out(buffer)
send "exit\r"
puts "$output\r\n"

Note that I changed the $password variable to $pass to be consistent with the other answer.