Python, how to read bytes from file and save it? [closed]

I want to read bytes from a file and then write those bytes to another file, and save that file.

How do I do this?

Solution 1:

Here's how to do it with the basic file operations in Python. This opens one file, reads the data into memory, then opens the second file and writes it out.

in_file = open("in-file", "rb") # opening for [r]eading as [b]inary
data = in_file.read() # if you only wanted to read 512 bytes, do .read(512)
in_file.close()

out_file = open("out-file", "wb") # open for [w]riting as [b]inary
out_file.write(data)
out_file.close()

We can do this more succinctly by using the with keyboard to handle closing the file.

with open("in-file", "rb") as in_file, open("out-file", "wb") as out_file:
    out_file.write(in_file.read())

If you don't want to store the entire file in memory, you can transfer it in pieces.

piece_size = 4096 # 4 KiB

with open("in-file", "rb") as in_file, open("out-file", "wb") as out_file:
    while True:
        piece = in_file.read(piece_size)

        if piece == "":
            break # end of file

        out_file.write(piece)

Solution 2:

In my examples I use the 'b' flag ('wb', 'rb') when opening the files because you said you wanted to read bytes. The 'b' flag tells Python not to interpret end-of-line characters which can differ between operating systems. If you are reading text, then omit the 'b' and use 'w' and 'r' respectively.

This reads the entire file in one chunk using the "simplest" Python code. The problem with this approach is that you could run out memory when reading a large file:

ifile = open(input_filename,'rb')
ofile = open(output_filename, 'wb')
ofile.write(ifile.read())
ofile.close()
ifile.close()

This example is refined to read 1MB chunks to ensure it works for files of any size without running out of memory:

ifile = open(input_filename,'rb')
ofile = open(output_filename, 'wb')
data = ifile.read(1024*1024)
while data:
    ofile.write(data)
    data = ifile.read(1024*1024)
ofile.close()
ifile.close()

This example is the same as above but leverages using with to create a context. The advantage of this approach is that the file is automatically closed when exiting the context:

with open(input_filename,'rb') as ifile:
    with open(output_filename, 'wb') as ofile:
        data = ifile.read(1024*1024)
        while data:
            ofile.write(data)
            data = ifile.read(1024*1024)

See the following:

• Python open(): http://docs.python.org/library/functions.html#open
• Python read(): http://docs.python.org/library/stdtypes.html#file.read
• Python write(): http://docs.python.org/library/stdtypes.html#file.write
• Dive into Python File Object Tutorial: http://diveintopython.net/file_handling/file_objects.html

Solution 3:

with open("input", "rb") as input:
    with open("output", "wb") as output:
        while True:
            data = input.read(1024)
            if data == "":
                break
            output.write(data)

The above will read 1 kilobyte at a time, and write it. You can support incredibly large files this way, as you won't need to read the entire file into memory.