Lambda/Linq with Contains criteria for multiple keywords
Solution 1:
Added extension method which can help in generating such predicate. Usage is simple:
var newList = MainList
.FilterByItems(keywords, (m, k) => m.Comments.Contains(k), true)
.ToList();
And implementation:
public static class QueryableExtensions
{
public static IQueryable<T> FilterByItems<T, TItem>(this IQueryable<T> query, IEnumerable<TItem> items,
Expression<Func<T, TItem, bool>> filterPattern, bool isOr)
{
Expression predicate = null;
foreach (var item in items)
{
var itemExpr = Expression.Constant(item);
var itemCondition = ExpressionReplacer.Replace(filterPattern.Body, filterPattern.Parameters[1], itemExpr);
if (predicate == null)
predicate = itemCondition;
else
{
predicate = Expression.MakeBinary(isOr ? ExpressionType.OrElse : ExpressionType.AndAlso, predicate,
itemCondition);
}
}
predicate ??= Expression.Constant(false);
var filterLambda = Expression.Lambda<Func<T, bool>>(predicate, filterPattern.Parameters[0]);
return query.Where(filterLambda);
}
class ExpressionReplacer : ExpressionVisitor
{
readonly IDictionary<Expression, Expression> _replaceMap;
public ExpressionReplacer(IDictionary<Expression, Expression> replaceMap)
{
_replaceMap = replaceMap ?? throw new ArgumentNullException(nameof(replaceMap));
}
public override Expression Visit(Expression exp)
{
if (exp != null && _replaceMap.TryGetValue(exp, out var replacement))
return replacement;
return base.Visit(exp);
}
public static Expression Replace(Expression expr, Expression toReplace, Expression toExpr)
{
return new ExpressionReplacer(new Dictionary<Expression, Expression> { { toReplace, toExpr } }).Visit(expr);
}
public static Expression Replace(Expression expr, IDictionary<Expression, Expression> replaceMap)
{
return new ExpressionReplacer(replaceMap).Visit(expr);
}
public static Expression GetBody(LambdaExpression lambda, params Expression[] toReplace)
{
if (lambda.Parameters.Count != toReplace.Length)
throw new InvalidOperationException();
return new ExpressionReplacer(Enumerable.Range(0, lambda.Parameters.Count)
.ToDictionary(i => (Expression) lambda.Parameters[i], i => toReplace[i])).Visit(lambda.Body);
}
}
}