There are a few different options on how to do this. The most basic is to use varargin, and then use nargin, size etc. to determine whether the optional arguments have been passed to the function.

% Function that takes two arguments, X & Y, followed by a variable 
% number of additional arguments
function varlist(X,Y,varargin)
   fprintf('Total number of inputs = %d\n',nargin);

   nVarargs = length(varargin);
   fprintf('Inputs in varargin(%d):\n',nVarargs)
   for k = 1:nVarargs
      fprintf('   %d\n', varargin{k})
   end

A little more elegant looking solution is to use the inputParser class to define all the arguments expected by your function, both required and optional. inputParser also lets you perform type checking on all arguments.


A simple way of doing this is via nargin (N arguments in). The downside is you have to make sure that your argument list and the nargin checks match.

It is worth remembering that all inputs are optional, but the functions will exit with an error if it calls a variable which is not set. The following example sets defaults for b and c. Will exit if a is not present.

function [ output_args ] = input_example( a, b, c )
if nargin < 1
  error('input_example :  a is a required input')
end

if nargin < 2
  b = 20
end

if nargin < 3
  c = 30
end
end

A good way of going about this is not to use nargin, but to check whether the variables have been set using exist('opt', 'var').

Example:

function [a] = train(x, y, opt)
    if (~exist('opt', 'var'))
        opt = true;
    end
end

See this answer for pros of doing it this way: How to check whether an argument is supplied in function call?