How to get nodes lying inside a range with javascript?
Solution 1:
Here's an implementation I came up with to solve this:
function getNextNode(node)
{
if (node.firstChild)
return node.firstChild;
while (node)
{
if (node.nextSibling)
return node.nextSibling;
node = node.parentNode;
}
}
function getNodesInRange(range)
{
var start = range.startContainer;
var end = range.endContainer;
var commonAncestor = range.commonAncestorContainer;
var nodes = [];
var node;
// walk parent nodes from start to common ancestor
for (node = start.parentNode; node; node = node.parentNode)
{
nodes.push(node);
if (node == commonAncestor)
break;
}
nodes.reverse();
// walk children and siblings from start until end is found
for (node = start; node; node = getNextNode(node))
{
nodes.push(node);
if (node == end)
break;
}
return nodes;
}
Solution 2:
The getNextNode will skip your desired endNode recursively if its a parent node.
Perform the conditional break check inside of the getNextNode instead:
var getNextNode = function(node, skipChildren, endNode){
//if there are child nodes and we didn't come from a child node
if (endNode == node) {
return null;
}
if (node.firstChild && !skipChildren) {
return node.firstChild;
}
if (!node.parentNode){
return null;
}
return node.nextSibling
|| getNextNode(node.parentNode, true, endNode);
};
and in while statement:
while (startNode = getNextNode(startNode, false , endNode));