How can I divide two integers to get a double?

How do I divide two integers to get a double?

You want to cast the numbers:

double num3 = (double)num1/(double)num2;

Note: If any of the arguments in C# is a double, a double divide is used which results in a double. So, the following would work too:

double num3 = (double)num1/num2;

For more information see:

Dot Net Perls

Complementing the @NoahD's answer

To have a greater precision you can cast to decimal:

(decimal)100/863
//0.1158748551564310544611819235

Or:

Decimal.Divide(100, 863)
//0.1158748551564310544611819235

Double are represented allocating 64 bits while decimal uses 128

(double)100/863
//0.11587485515643106

In depth explanation of "precision"

For more details about the floating point representation in binary and its precision take a look at this article from Jon Skeet where he talks about floats and doubles and this one where he talks about decimals.

cast the integers to doubles.

Convert one of them to a double first. This form works in many languages:

 real_result = (int_numerator + 0.0) / int_denominator