What does <T> (angle brackets) mean in Java?

I am currently studying Java and have recently been stumped by angle brackets(<>). What exactly do they mean?

public class Pool<T>{
    public interface PoolFactory<T>{
        public T createObject();
    }
    this.freeObjects = new ArrayList<T>(maxsize)
}

What does the <T> mean? Does it means that I can create an object of type T?

<T> is a generic and can usually be read as "of type T". It depends on the type to the left of the <> what it actually means.

I don't know what a Pool or PoolFactory is, but you also mention ArrayList<T>, which is a standard Java class, so I'll talk to that.

Usually, you won't see "T" in there, you'll see another type. So if you see ArrayList<Integer> for example, that means "An ArrayList of Integers." Many classes use generics to constrain the type of the elements in a container, for example. Another example is HashMap<String, Integer>, which means "a map with String keys and Integer values."

Your Pool example is a bit different, because there you are defining a class. So in that case, you are creating a class that somebody else could instantiate with a particular type in place of T. For example, I could create an object of type Pool<String> using your class definition. That would mean two things:

My Pool<String> would have an interface PoolFactory<String> with a createObject method that returns Strings.
Internally, the Pool<String> would contain an ArrayList of Strings.

This is great news, because at another time, I could come along and create a Pool<Integer> which would use the same code, but have Integer wherever you see T in the source.

It's really simple. It's a new feature introduced in J2SE 5. Specifying angular brackets after the class name means you are creating a temporary data type which can hold any type of data.

Example:

class A<T>{
    T obj;
    void add(T obj){
        this.obj=obj;
    }
    T get(){
        return obj;
    }
}
public class generics {
    static<E> void print(E[] elements){
        for(E element:elements){
            System.out.println(element);
        }
    }

    public static void main(String[] args) {
        A<String> obj=new A<String>();
        A<Integer> obj1=new A<Integer>();
        obj.add("hello");
        obj1.add(6);
        System.out.println(obj.get());
        System.out.println(obj1.get());

        Integer[] arr={1,3,5,7};
        print(arr);
    }
}

Instead of <T>, you can actually write anything and it will work the same way. Try writing <ABC> in place of <T>.

This is just for convenience:

<T> is referred to as any type
<E> as element type
<N> as number type
<V> as value
<K> as key

But you can name it anything you want, it doesn't really matter.

Moreover, Integer, String, Boolean etc are wrapper classes of Java which help in checking of types during compilation. For example, in the above code, obj is of type String, so you can't add any other type to it (try obj.add(1), it will cast an error). Similarly, obj1 is of the Integer type, you can't add any other type to it (try obj1.add("hello"), error will be there).

It is related to generics in java. If I mentioned ArrayList<String> that means I can add only String type object to that ArrayList.

The two major benefits of generics in Java are:

Reducing the number of casts in your program, thus reducing the number of potential bugs in your program.
Improving code clarity

is called a generic type. You can instantiate an object Pool like this:

PoolFactory<Integer> pool = new Pool<Integer>();

The generic parameter can only be a reference type. So you can't use primitive types like int or double or char or other primitive types.

What does <T> (angle brackets) mean in Java?

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