Doesn't the constant matter in $\int\frac{1}{x}dx=\ln(kx)+C$ instead of writing $\ln(x)+C$?
$\ln kx=\ln k+\ln x$ and $\ln k$ is a constant so it doesn't matter.
Doesn't the constant matter in $\int\frac{1}{x}dx=\ln(kx)+C$ instead of writing $\ln(x)+C$?
$\ln kx=\ln k+\ln x$ and $\ln k$ is a constant so it doesn't matter.