Assign string containing null-character (\0) to a variable in Bash
In Bash, you can't store the NULL-character in a variable.
You may, however, store a plain hex dump of the data (and later reverse this operation again) by using the xxd
command.
VAR1=`echo -ne "n\0m\0k" | xxd -p | tr -d '\n'`
echo -ne "$VAR1" | xxd -r -p | od -c # -> 0000000 n \0 m \0 k
As others have already stated, you can't store/use NUL char:
- in a variable
- in an argument of the command line.
However, you can handle any binary data (including NUL char):
- in pipes
- in files
So to answer your last question:
can anybody give me a hint how strings containing \0 chars can be stored or handled efficiently without losing any (meta-) characters?
You can use files or pipes to store and handle efficiently any string with any meta-characters.
If you plan to handle data, you should note additionally that:
- Only the NUL char will be eaten by variable and argument of the command line, you can check this.
- Be wary that command substitution (as
$(command..)
or`command..`
) has an additional twist above being a variable as it'll eat your ending new lines.
Bypassing limitations
If you want to use variables, then you must get rid of the NUL char by encoding it, and various other solutions here give clever ways to do that (an obvious way is to use for example base64 encoding/decoding).
If you are concerned by memory or speed, you'll probably want to use a minimal parser and only quote NUL character (and the quoting char). In this case this would help you:
quote() { sed 's/\\/\\\\/g;s/\x0/\\x00/g'; }
Then, you can secure your data before storing them in variables and
command line argument by piping your sensitive data into quote
, which will output a safe data stream without NUL chars. You can get back
the original string (with NUL chars) by using echo -en "$var_quoted"
which will send the correct string on the standard output.
Example:
## Our example output generator, with NUL chars
ascii_table() { echo -en "$(echo '\'0{0..3}{0..7}{0..7} | tr -d " ")"; }
## store
myvar_quoted=$(ascii_table | quote)
## use
echo -en "$myvar_quoted"
Note: use | hd
to get a clean view of your data in hexadecimal and
check that you didn't loose any NUL chars.
Changing tools
Remember you can go pretty far with pipes without using variables nor argument in command line, don't forget for instance the <(command ...)
construct that will create a named pipe (sort of a temporary file).
EDIT: the first implementation of quote
was incorrect and would not deal correctly with \
special characters interpreted by echo -en
. Thanks @xhienne for spotting that.
EDIT2: the second implementation of quote
had bug because of using only \0
than would actually eat up more zeroes as \0
, \00
, \000
and \0000
are equivalent. So \0
was replaced by \x00
. Thanks for @MatthijsSteen for spotting this one.
Use uuencode
and uudecode
for POSIX portability
xxd
and base64
are not POSIX 7 but uuencode is.
VAR="$(uuencode -m <(printf "a\0\n") /dev/stdout)"
uudecode -o /dev/stdout <(printf "$VAR") | od -tx1
Output:
0000000 61 00 0a
0000003
Unfortunately I don't see a POSIX 7 alternative for the Bash process <()
substitution extension except writing to file, and they are not installed in Ubuntu 12.04 by default (sharutils
package).
So I guess that the real answer is: don't use Bash for this, use Python or some other saner interpreted language.
I love jeff's answer. I would use Base64 encoding instead of xxd. It saves a little space and would be (I think) more recognizable as to what is intended.
VAR=$(echo -ne "foo\0bar" | base64)
echo -n "$VAR" | base64 -d | xargs -0 ...
As for -e, it is needed for the echo of a literal string with an encoded null ('\0'), though I also seem to recall something about "echo -e" being unsafe if you're echoing any user input as they could inject escape sequences that echo will interpret and end up with bad things. The -e flag is not needed when echoing the encoded stored string into the decode.