Complete word matching using grepl in R
Consider the following example:
> testLines <- c("I don't want to match this","This is what I want to match")
> grepl('is',testLines)
> [1] TRUE TRUE
What I want, though, is to only match 'is' when it stands alone as a single word. From reading a bit of perl documentation, it seemed that the way to do this is with \b, an anchor that can be used to identify what comes before and after the patter, i.e. \bword\b matches 'word' but not 'sword'. So I tried the following example, with use of Perl syntax set to 'TRUE':
> grepl('\bis\b',testLines,perl=TRUE)
> [1] FALSE FALSE
The output I'm looking for is FALSE TRUE
.
Solution 1:
"\<" is another escape sequence for the beginning of a word, and "\>" is the end. In R strings you need to double the backslashes, so:
> grepl("\\<is\\>", c("this", "who is it?", "is it?", "it is!", "iso"))
[1] FALSE TRUE TRUE TRUE FALSE
Note that this matches "is!" but not "iso".
Solution 2:
you need double-escaping to pass escape to regex:
> grepl("\\bis\\b",testLines)
[1] FALSE TRUE
Solution 3:
Very simplistically, match on a leading space:
testLines <- c("I don't want to match this","This is what I want to match")
grepl(' is',testLines)
[1] FALSE TRUE
There's a whole lot more than this to regular expressions, but essentially the pattern needs to be more specific. What you will need in more general cases is a huge topic. See ?regex
Other possibilities that will work for this example:
grepl(' is ',testLines)
[1] FALSE TRUE
grepl('\\sis',testLines)
[1] FALSE TRUE
grepl('\\sis\\s',testLines)
[1] FALSE TRUE