Variadic template templates and perfect forwarding

That's exactly right. I would expect it to work. So I think that GCC is in error with rejecting that. FWIW:

#include <utility>

template <template <typename...> class TemplateClass, typename... Args>
TemplateClass<Args...> make(Args&&... args)
{
    return TemplateClass<Args...>(std::forward<Args>(args)...);
}

int main() {
  make<std::pair>(1, 2);
}


// [js@HOST2 cpp]$ clang++ -std=c++0x main1.cpp
// [js@HOST2 cpp]$

This is probably a GCC quirk. I can get the following to work with a dev snapshot (I don't have a copy of 4.6 right now):

template<
    template<typename...> class TemplateClass
    , typename... Args

    , typename Result = TemplateClass<Args...>
    // Also works with the arguably more correct
    // , typename Result = TemplateClass<
    //     typename std::decay<Args>::type...
    // >
>
Result
make(Args&&... args)
{ /* as before */ }