Regular expression matching E.164 formatted phone numbers
I need to add a regular expression that matches all possible valid E.164 formatted phone numbers.
This regex works fine for for North American phone numbers, but I need something that will work for international numbers as well:
^(+1|1)?([2-9]\d\d[2-9]\d{6})$
Example: +13172222222 matches 13172222222 still matches because +1 or 1 are optional 3172222222 still matches because +1 or 1 are optional 3171222222 does not match and is not a valid NANPA number.
Source: Freeswitch.org
I also came across this related question, but I think that it is way too crazy for my needs. In my case, I am simply validating an entry for a blacklist, which I'm comparing to incoming Twilio data; so, I care much less about weather a country code is valid. I really only need to test if a number matches the general E.164 form, rather than assuming it's a NANPA.
To be better understand what I need to match, here is an example from the Twilio Documentation:
All phone numbers in requests from Twilio are in E.164 format if possible. For example, (415) 555-4345 would come through as '+14155554345'. However, there are occasionally cases where Twilio cannot normalize an incoming caller ID to E.164. In these situations Twilio will report the raw caller ID string.
I want to match something like +14155554345, but not (415) 555-4345, 415555434, 555-4345 or 5554345. The regex should not restrict itself to only matching the US country code though. Basically, it should match the +xxxxxxxxxxx format. I also think the number could be longer, as there are multi-digit country codes, such as in the UK. T-Mobile's UK number is +447953966150 I'll update this if I can come up with a better example.
Solution 1:
The accepted answer is good, except an E.164 number can have up to 15 digits. The specification also doesn't indicate a minimum, so I wouldn't necessarily count on 10.
It should be ^\+?[1-9]\d{1,14}$
See http://en.wikipedia.org/wiki/E.164
Solution 2:
I think until you have a great set of examples, you are best served by a flexible regex. This one will match a +
followed by 10-14 digits.
^\+?\d{10,14}$
Broken down, this expression means:
^
Match begining of string.
\+?
Optionally match a +
symbol.
\d{10,14}
Match between 10 and 14 digits.
$
Ensure we are at the end of the string.
If you learn that a digit at a particular index must not be 1 or 0, then you can use the [2-9]
at that position, like this:
^\+?\d{6,7}[2-9]\d{3}$
[2-9]
means match any digit from 2 through 9 (don't match 0 or 1.)
Solution 3:
Well, I used the accepted answer but it failed for many cases:
For inputs like:
- Where numbers did not start with "+".
- Where number count was less than 9.
the regex failed.
I finally used
^\+(?:[0-9]?){6,14}[0-9]$
This worked like a charm!
Solution 4:
This matches only formats like +16174552211
and 16174552211
/\A\+?\d{11}\z/
It is especially useful if you are using Twilio and Ruby on Rails
Solution 5:
Typescript/Javascript : E.164
This works for me:
static PHONE_NUMBER = /^\+[1-9]\d{10,14}$/; // E.164
PHONE_NUMBER.test('+' + countryCode + phoneNumber);
Reference: https://blog.kevinchisholm.com/javascript/javascript-e164-phone-number-validation/