Pygame how to let balls collide
Solution 1:
To detect if 2 circles (respectively balls) are colliding, you've to test, if the Euclidean distance between the circles center points is less than the sum of the radii. I recommend to use pygame.math.Vector2
/ distance_to()
for the computation.
In the following the 1 circle is defined by the center point (x1, y1) and the radius r1. The 2nd circle is defined by (x2, y2) and r2:
v1 = pygame.math.Vector2(x1, y1)
v2 = pygame.math.Vector2(x2, y2)
if v1.distance_to(v2) < r1 + r2:
print("hit")
If you want to make the circles bounce, you have to reflect the motion vector of the circle at the normal vector of the intersection like a billiard ball. Use pygame.math.Vector2
/ reflect_ip()
or reflect()
to compute the new direction of the circle.
The movements of the circles are given by (mx1, my1) and (mx2, my2):
nv = v2 - v1
m1 = pygame.math.Vector2(mx1, my1).reflect(nv)
m2 = pygame.math.Vector2(mx2, my2).reflect(nv)
mx1, my1 = m1.x, m1.y
mx2, my2 = m2.x, m2.y
Minimal example: repl.it/@Rabbid76/PyGame-CirclesBounceOff
import pygame
pygame.init()
width, height = 400, 400
window = pygame.display.set_mode((width, height))
clock = pygame.time.Clock()
x1, y1, r1, mx1, my1 = 200, 200, 50, 2, 0.5
x2, y2, r2, mx2, my2 = 300, 200, 50, -1, -1.5
def move(c, v, r, m):
c += v
if c < r: c, v = r, -v
if c > m-r: c, v = m-r, -v
return c, v
hit_count = 0
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
x1, mx1 = move(x1, mx1, r1, width)
y1, my1 = move(y1, my1, r1, height)
x2, mx2 = move(x2, mx2, r2, width)
y2, my2 = move(y2, my2, r2, height)
v1 = pygame.math.Vector2(x1, y1)
v2 = pygame.math.Vector2(x2, y2)
if v1.distance_to(v2) < r1 + r2 - 2:
hit_count += 1
print("hit:", hit_count)
nv = v2 - v1
m1 = pygame.math.Vector2(mx1, my1).reflect(nv)
m2 = pygame.math.Vector2(mx2, my2).reflect(nv)
mx1, my1 = m1.x, m1.y
mx2, my2 = m2.x, m2.y
window.fill((127, 127, 127))
pygame.draw.circle(window, (255, 0, 0), (round(x1), round(y1)), r1, 4)
pygame.draw.circle(window, (0, 0, 255), (round(x2), round(y2)), r2, 4)
pygame.display.flip()