Solution 1:

Put anything into an array using Array.push().

var a=[], b={};
a.push(b);    
// a[0] === b;

Extra information on Arrays

Add more than one item at a time

var x = ['a'];
x.push('b', 'c');
// x = ['a', 'b', 'c']

Add items to the beginning of an array

var x = ['c', 'd'];
x.unshift('a', 'b');
// x = ['a', 'b', 'c', 'd']

Add the contents of one array to another

var x = ['a', 'b', 'c'];
var y = ['d', 'e', 'f'];
x.push.apply(x, y);
// x = ['a', 'b', 'c', 'd', 'e', 'f']
// y = ['d', 'e', 'f']  (remains unchanged)

Create a new array from the contents of two arrays

var x = ['a', 'b', 'c'];
var y = ['d', 'e', 'f'];
var z = x.concat(y);
// x = ['a', 'b', 'c']  (remains unchanged)
// y = ['d', 'e', 'f']  (remains unchanged)
// z = ['a', 'b', 'c', 'd', 'e', 'f']

Solution 2:

var years = [];
for (i= 2015;i<=2030;i=i+1){
    years.push({operator : i})
}

here array years is having values like

years[0]={operator:2015}
years[1]={operator:2016}

it continues like this.