How to hide a button programmatically?
I have a RelativeLayout
which contains two buttons. Which are overlapped on each other.
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#FFFFFF">
<Button android:text="Play"
android:id="@+id/play"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_alignParentBottom = "true">
</Button>
<Button android:text="Stop "
android:id="@+id/stop"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_alignParentBottom = "true">
</Button>
</RelativeLayout>
I want to programmatically show only one button at a time when its click event is called.
I tried it with :
playButton.setVisibility(1);
but it does not worked. Following is an example what I am trying to do.
playButton = (Button) findViewById(R.id.play);
playButton.setVisibility(1);
playButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//when play is clicked show stop button and hide play button
}
});
Solution 1:
You can use the following code:
playButton = (Button) findViewById(R.id.play);
playButton.setVisibility(View.VISIBLE);
playButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//when play is clicked show stop button and hide play button
playButton.setVisibility(View.GONE);
stopButton.setVisibility(View.VISIBLE);
}
});
Solution 2:
Try the below code -
playButton.setVisibility(View.INVISIBLE);
or -
playButton.setVisibility(View.GONE);
show it again with -
playButton.setVisibility(View.VISIBLE);
Solution 3:
In Kotlin
myButton.visibility = View.GONE
Solution 4:
Hidde:
BUTTON.setVisibility(View.GONE);
Show:
BUTTON.setVisibility(View.VISIBLE);
Solution 5:
Please used below
View.GONE and View.VISIBLE