Solve $f^2(x)=x+f(x+1)$
If the function $f(x)$ is such that $$f^2(x)=x+f(x+1),$$ find a closed-form expression for $f$.
I found $$f(x)=\sqrt{x+\sqrt{x+1+\sqrt{x+2+\sqrt{x+3+\cdots}}}}$$ is such an $f$. Does anyone have other solutions? Thank you.
Solution 1:
You can always take either square-root, so $$ f(x)=\pm\sqrt{x\pm\sqrt{x+1\pm\sqrt{x+2\pm\sqrt{x+3\pm\cdots}}}} $$ Gives you uncountably many solutions...