Maintaining session in android ( application stay authenticated on the server side)
Solution 1:
Finally I solved the issue of session handling in Android. Android cant handle the session itself(which a simple browser can) so we have to handle it explicitly. I changed the code for http connection a bit. Created an instance of DefaultHttpClient in the first Activity when connection established.
public static DefaultHttpClient httpClient;
For the first time connection,I did the following:
URL url=new URL(urlToHit);
LoginScreen.httpClient = new DefaultHttpClient(); //LoginScreen is the name of the current Activity
HttpPost httppost = new HttpPost(url.toString());
HttpResponse response = LoginScreen.httpClient.execute(httppost);
xr.parse(new InputSource(url.openStream())); //SAX parsing
Now for all further connections I used the same httpClient For example in the next activity:
URL url=new URL(urlToHit);
HttpPost httppost = new HttpPost(url.toString());
HttpResponse response = LoginScreen.httpClient.execute(httppost);
// Log.v("response code",""+response.getStatusLine().getStatusCode());
// Get hold of the response entity
HttpEntity entity = response.getEntity();
InputStream instream = null;
if (entity != null) {
instream = entity.getContent();
}
xr.parse(new InputSource(instream)); //SAX parsing
Hope this will help you all too to solve session issue in Android.
Solution 2:
The best idea is to put all the function that your server do in on unique class which is going to be call by the tasks which want to connect. I call this class WebServiceManager. This class have exactly the same method than the server.
As you want an unique session do :
private static WebServiceManager wsm = null;
public static WebServiceManager getInstance() {
if (wsm == null) {
wsm = new WebServiceManager();
}
return wsm;
}
private final HttpClient httpClient;
private WebServiceManager() {
httpClient=new DefaultHttpClient();
}
and then you call the method of your instance of webServiceManager to use always the same session. :)
Solution 3:
My problem was that i login first and saved the returned session in userpreferences. After that the POST call to set a record said
"Error ,Cannot authenticate the User"
So i added
post.setHeader("oAuth-Token", UserPreferences.ACCESS_TOKEN);
the whole thing looks like this.
HttpPost post=new HttpPost(URL );
post.setHeader("oAuth-Token", UserPreferences.ACCESS_TOKEN);
. . and It solved the problem.
Solution 4:
I wrote a post about it a while back on coderwall It uses the HttpRequestInterceptor and HttpResponseInterceptor classes which are perfect for that kind of scenario.
Here is an example:
public class HTTPClients {
private static DefaultHttpClient _defaultClient;
private static String session_id;
private static HTTPClients _me;
private HTTPClients() {
}
public static DefaultHttpClient getDefaultHttpClient(){
if ( _defaultClient == null ) {
_defaultClient = new DefaultHttpClient();
_me = new HTTPClients();
_defaultClient.addResponseInterceptor(_me.new SessionKeeper());
_defaultClient.addRequestInterceptor(_me.new SessionAdder());
}
return _defaultClient;
}
private class SessionAdder implements HttpRequestInterceptor {
@Override
public void process(HttpRequest request, HttpContext context)
throws HttpException, IOException {
if ( session_id != null ) {
request.setHeader("Cookie", session_id);
}
}
}
private class SessionKeeper implements HttpResponseInterceptor {
@Override
public void process(HttpResponse response, HttpContext context)
throws HttpException, IOException {
Header[] headers = response.getHeaders("Set-Cookie");
if ( headers != null && headers.length == 1 ){
session_id = headers[0].getValue();
}
}
}
}
Solution 5:
Here is an another implementation using Volley library ... a very useful hint from https://stackoverflow.com/a/36496607/3099185
CustomRequest jsonObjReq = new CustomRequest(Request.Method.GET,
url, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.d(TAG, response.toString());
}
}, new Response.ErrorListener(){
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG, "Error: " + error.getMessage());
Toast.makeText(getApplicationContext(),
error.getMessage(), Toast.LENGTH_SHORT).show();
// hide the progress dialog
}
});
Custom request class
import android.util.Log;
import com.android.volley.AuthFailureError;
import com.android.volley.Response;
import com.android.volley.toolbox.JsonObjectRequest;
import org.json.JSONObject;
import java.util.HashMap;
import java.util.Map;
public class CustomRequest extends JsonObjectRequest {
private String session_id = "";
public CustomRequest(int method, String url, JSONObject jsonRequest,
Response.Listener listener, Response.ErrorListener errorListener) {
super(method, url, jsonRequest, listener, errorListener);
}
public CustomRequest(int method, String url, JSONObject jsonRequest, String session_id,
Response.Listener listener, Response.ErrorListener errorListener) {
super(method, url, jsonRequest, listener, errorListener);
this.session_id = session_id;
}
@Override
public Map getHeaders() throws AuthFailureError {
Map headers = new HashMap();
Log.d(TAG, " -> session_id = " + session_id);
if(!(session_id.equals(""))) {
headers.put("Cookie", this.session_id);
}
return headers;
}
}
Simple way of implementing volley using singleton pattern http://arnab.ch/blog/2013/08/asynchronous-http-requests-in-android-using-volley/
Remember to initialize mRequestQueue in onCreate() to avoid unexpected null pointer exception
@Override
public void onCreate() {
super.onCreate();
// initialize the singleton
sInstance = this;
mRequestQueue = Volley.newRequestQueue(this);
}
Hope this help too ... ! :)