How to create abstract properties in python abstract classes

In the following code, I create a base abstract class Base. I want all the classes that inherit from Base to provide the name property, so I made this property an @abstractmethod.

Then I created a subclass of Base, called Base_1, which is meant to supply some functionality, but still remain abstract. There is no name property in Base_1, but nevertheless python instatinates an object of that class without an error. How does one create abstract properties?

from abc import ABCMeta, abstractmethod

class Base(object):
    __metaclass__ = ABCMeta
    def __init__(self, strDirConfig):
        self.strDirConfig = strDirConfig
    
    @abstractmethod
    def _doStuff(self, signals):
        pass
    
    @property    
    @abstractmethod
    def name(self):
        # this property will be supplied by the inheriting classes
        # individually
        pass
    

class Base_1(Base):
    __metaclass__ = ABCMeta
    # this class does not provide the name property, should raise an error
    def __init__(self, strDirConfig):
        super(Base_1, self).__init__(strDirConfig)
    
    def _doStuff(self, signals):
        print 'Base_1 does stuff'
        

class C(Base_1):
    @property
    def name(self):
        return 'class C'
    
        
if __name__ == '__main__':
    b1 = Base_1('abc')  

Solution 1:

Since Python 3.3 a bug was fixed meaning the property() decorator is now correctly identified as abstract when applied to an abstract method.

Note: Order matters, you have to use @property above @abstractmethod

Python 3.3+: (python docs):

from abc import ABC, abstractmethod

class C(ABC):
    @property
    @abstractmethod
    def my_abstract_property(self):
        ...

Python 2: (python docs)

from abc import ABC, abstractproperty

class C(ABC):
    @abstractproperty
    def my_abstract_property(self):
        ...

Solution 2:

Until Python 3.3, you cannot nest @abstractmethod and @property.

Use @abstractproperty to create abstract properties (docs).

from abc import ABCMeta, abstractmethod, abstractproperty

class Base(object):
    # ...
    @abstractproperty
    def name(self):
        pass

The code now raises the correct exception:

Traceback (most recent call last):
  File "foo.py", line 36, in 
    b1 = Base_1('abc')  
TypeError: Can't instantiate abstract class Base_1 with abstract methods name

Solution 3:

Based on James answer above

def compatibleabstractproperty(func):

    if sys.version_info > (3, 3):             
        return property(abstractmethod(func))
    else:
        return abstractproperty(func)

and use it as a decorator

@compatibleabstractproperty
def env(self):
    raise NotImplementedError()

Solution 4:

Using the @property decorator in the abstract class (as recommended in the answer by James) works if you want the required instance level attributes to use the property decorator as well.

If you don't want to use the property decorator, you can use super(). I ended up using something like the __post_init__() from dataclasses and it gets the desired functionality for instance level attributes:

import abc
from typing import List

class Abstract(abc.ABC):
    """An ABC with required attributes.

    Attributes:
        attr0
        attr1 
    """

    @abc.abstractmethod
    def __init__(self):
        """Forces you to implement __init__ in 'Concrete'. 
        Make sure to call __post_init__() from inside 'Concrete'."""

    def __post_init__(self):
        self._has_required_attributes()
        # You can also type check here if you want.

    def _has_required_attributes(self):
        req_attrs: List[str] = ['attr0', 'attr1']
        for attr in req_attrs:
            if not hasattr(self, attr):
                raise AttributeError(f"Missing attribute: '{attr}'")

class Concrete(Abstract):

    def __init__(self, attr0, attr1):
        self.attr0 = attr0
        self.attr1 = attr1
        self.attr2 = "some value" # not required
        super().__post_init__() # Enforces the attribute requirement.