Recursively list full absolute path of files with permissions in Linux

I have done a bit of searching online, and I am trying to find a way to recursively list all files with their absolute path and with their permissions. I want to do this so that I can grep out what I want, so that when I run the command, I can get just the matching files, their permissions, and their full paths, like:

<search command> | grep file.name

Output:

/home/current/Desktop/file.name
/etc/program/src/file.name

I would prefer to use ls because it is the fastest, and I would type:

ls -alR $PWD/

But this doesn't show the file's path, so if I grep'ed the output, then I would see file permissions, but not the directory from which it originated.

I can use ls integrated with find and grep to get the output in exactly the format that I want, and I could use something like this:

ls -ault `find $PWD/ -type f` | grep file.name

But this is extremely slow, I'm guessing because two commands are actually running.

If I just use find without ls or grep, then it goes faster, but it is a bunch to type:

find $PWD/ -type f -name file.name -printf '%M %u %g %s\t%a\t%p\r\n'

This will give me a nice format (It also includes the user, group, size, and last date of access, which are helpful). However, it is a ton to type, and it is certainly not as fast as using ls with grep.

Is there a faster way to do what I am trying to do than to use find?

Solution 1:

Rather than ls or find you may try tree. Specifically tree -ifpugDs $PWD should give you what you would like.

-if removes indentation lines and prints out path

-p prints permissions

-ug prints user and group

-D prints modification time

-s prints size

Solution 2:

If typing it is a problem, what about putting what you already have in a function:

myspecialfinder() {
  find $PWD/ -type f -name "$1" -printf '%M %u %g %s\t%a\t%p\r\n'
}

You would use it as

myspecialfinder file.name

Solution 3:

Simple answer: find -type f -print0 | xargs -0 ls -al