How to use std::sort to sort an array in C++
How to use standard template library std::sort()
to sort an array declared as
int v[2000]
;
Does C++ provide some function that can get the begin and end index of an array?
In C++0x/11 we get std::begin
and std::end
which are overloaded for arrays:
#include <algorithm>
int main(){
int v[2000];
std::sort(std::begin(v), std::end(v));
}
If you don't have access to C++0x, it isn't hard to write them yourself:
// for container with nested typedefs, non-const version
template<class Cont>
typename Cont::iterator begin(Cont& c){
return c.begin();
}
template<class Cont>
typename Cont::iterator end(Cont& c){
return c.end();
}
// const version
template<class Cont>
typename Cont::const_iterator begin(Cont const& c){
return c.begin();
}
template<class Cont>
typename Cont::const_iterator end(Cont const& c){
return c.end();
}
// overloads for C style arrays
template<class T, std::size_t N>
T* begin(T (&arr)[N]){
return &arr[0];
}
template<class T, std::size_t N>
T* end(T (&arr)[N]){
return arr + N;
}
#include <algorithm>
static const size_t v_size = 2000;
int v[v_size];
// Fill the array by values
std::sort(v,v+v_size);
In C++11:
#include <algorithm>
#include <array>
std::array<int, 2000> v;
// Fill the array by values
std::sort(v.begin(),v.end());
If you don't know the size, you can use:
std::sort(v, v + sizeof v / sizeof v[0]);
Even if you do know the size, it's a good idea to code it this way as it will reduce the possibility of a bug if the array size is changed later.
You can sort it std::sort(v, v + 2000)
//It is working
#include<iostream>
using namespace std;
void main()
{
int a[5];
int temp=0;
cout<<"Enter Values"<<endl;
for(int i=0;i<5;i++)
{
cin>>a[i];
}
for(int i=0;i<5;i++)
{
for(int j=0;j<5;j++)
{
if(a[i]>a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
cout<<"Asending Series"<<endl;
for(int i=0;i<5;i++)
{
cout<<endl;
cout<<a[i]<<endl;
}
for(int i=0;i<5;i++)
{
for(int j=0;j<5;j++)
{
if(a[i]<a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
cout<<"Desnding Series"<<endl;
for(int i=0;i<5;i++)
{
cout<<endl;
cout<<a[i]<<endl;
}
}