Detect if bat file is running via double click or from cmd window
mousio's solution is nice; however, I personally did not manage to make it work in an "IF" statement because of the double quotes in the value of %cmdcmdline% (with or without double quotes around %cmdcmdline%).
In constrast, the solution using %0 works fine. I used the following block statement and it works like a charm:
IF %0 == "%~0" pause
The following solution, which expands %~0 to a fully qualified path, might also work if the previous does not (cf. Alex Essilfie's comment):
IF %0 EQU "%~dpnx0" PAUSE
However, note that this solution with %~dpnx0 fails when
- the .bat file is located somewhere in the
%USERPROFILE%directory, and - your
%USERNAME%contains one or more uppercase characters
because... wait for it... the d in %~dpnx0 forces your %USERPROFILE% username to lowercase, while plain %0 does not. So they're never equal if your username contains an uppercase character. ¯\_(ツ)_/¯
[Edit 18 June 2021 - thanks to JasonXA]
You can solve this lowercase issue with case-insensitive comparison (magic /I):
IF /I %0 EQU "%~dpnx0" PAUSE
This might be the best solution of all!
%cmdcmdline% gives the exact command line used to start the current Cmd.exe.
- When launched from a command console, this var is
"%SystemRoot%\system32\cmd.exe". - When launched from explorer this var is
cmd /c ""{full_path_to_the_bat_file}" ";
this implicates that you might also check the%0variable in your bat file, for in this case it is always the full path to the bat file, and always enclosed in double quotes.
Personally, I would go for the %cmdcmdline% approach (not %O), but be aware that both start commands can be overridden in the registry…