Why does someNumber = rand() & 100 + 1; not produce an error?
Solution 1:
It's the bitwise and operator. It takes two numbers, then it "ands" their bits.
For example: 3 & 10 is 2.
0011
&1010
----
0010
Solution 2:
There's no error because it's a perfectly legal expression. The result of the call to rand() is bitwise-anded with the result of 100 + 1.