How many bytes is unsigned long long?

Executive summary: it's 64 bits, or larger.

unsigned long long is the same as unsigned long long int. Its size is platform-dependent, but guaranteed by the C standard (ISO C99) to be at least 64 bits. There was no long long in C89, but apparently even MSVC supports it, so it's quite portable.

In the current C++ standard (issued in 2003), there is no long long, though many compilers support it as an extension. The upcoming C++0x standard will support it and its size will be the same as in C, so at least 64 bits.

You can get the exact size, in bytes (8 bits on typical platforms) with the expression sizeof(unsigned long long). If you want exactly 64 bits, use uint64_t, which is defined in the header <stdint.h> along with a bunch of related types (available in C99, C++11 and some current C++ compilers).

The beauty of C++, like C, is that the sized of these things are implementation-defined, so there's no correct answer without your specifying the compiler you're using. Are those two the same? Yes. "long long" is a synonym for "long long int", for any compiler that will accept both.

It must be at least 64 bits. Other than that it's implementation defined.

Strictly speaking, unsigned long long isn't standard in C++ until the C++0x standard. unsigned long long is a 'simple-type-specifier' for the type unsigned long long int (so they're synonyms).

The long long set of types is also in C99 and was a common extension to C++ compilers even before being standardized.

Use the operator sizeof, it will give you the size of a type expressed in byte. One byte is eight bits. See the following program:

#include <iostream>

int main(int,char**)
{
 std::cout << "unsigned long long " << sizeof(unsigned long long) << "\n";
 std::cout << "unsigned long long int " << sizeof(unsigned long long int) << "\n";
 return 0;
}