How do I create a PDO parameterized query with a LIKE statement?

Figured it out right after I posted:

$query = $database->prepare('SELECT * FROM table WHERE column LIKE ?');
$query->execute(array('value%'));

while ($results = $query->fetch())
{
    echo $results['column'];
}

For those using named parameters, here's how to use LIKE with % partial matching for MySQL databases:

WHERE column_name LIKE CONCAT('%', :dangerousstring, '%')

where the named parameter is :dangerousstring.

In other words, use explicitly unescaped % signs in your own query that are separated and definitely not the user input.

Edit: Concatenation syntax for Oracle databases uses the concatenation operator: ||, so it'll simply become:

WHERE column_name LIKE '%' || :dangerousstring || '%'

However there are caveats as @bobince mentions here that:

The difficulty comes when you want to allow a literal % or _ character in the search string, without having it act as a wildcard.

So that's something else to watch out for when combining like and parameterization.

$query = $database->prepare('SELECT * FROM table WHERE column LIKE ?');
$query->bindValue(1, "%$value%", PDO::PARAM_STR);
$query->execute();

if (!$query->rowCount() == 0) 
{
    while ($results = $query->fetch()) 
    {
        echo $results['column'] . "<br />\n";
    }       
} 
else 
{
    echo 'Nothing found';
}

You can also try this one. I face similar problem but got result after research.

$query = $pdo_connection->prepare('SELECT * FROM table WHERE column LIKE :search');

$stmt= $pdo_connection->prepare($query);

$stmt->execute(array(':search' => '%'.$search_term.'%'));

$result = $stmt->fetchAll(PDO::FETCH_ASSOC);

print_r($result);

How do I create a PDO parameterized query with a LIKE statement?

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