How to fix "set SameSite cookie to none" warning?

I created a chrome extension and from popup.js I called PHP script (Using Xhttprequest) that reads the cookie. Like this:

$cookie_name = "mycookie";

if(isset($_COOKIE[$cookie_name]))
{
    echo $_COOKIE[$cookie_name];
}
else{
    echo "nocookie";
}

But I'm getting this warning at errors in extensions.

A cookie associated with a cross-site resource at (Here is my domain) was set without the SameSite attribute. A future release of Chrome will only deliver cookies with cross-site requests if they are set with SameSite=None and Secure. You can review cookies in developer tools under Application>Storage>Cookies and see more details at https://www.chromestatus.com/feature/5088147346030592 and https://www.chromestatus.com/feature/5633521622188032.

I tried to create a cookie like this but it didn't help.

setcookie($cookie_name,$cookie_value, time() + 3600*24, "/;samesite=None ","mydomain.com", 1);

Following instructions from this question.

Solution 1:

I'm also in a "trial and error" for that, but this answer from Google Chrome Labs' Github helped me a little. I defined it into my main file and it worked - well, for only one third-party domain. Still making tests, but I'm eager to update this answer with a better solution :)

EDIT: I'm using PHP 7.4 now, and this syntax is working good (Sept 2020):

$cookie_options = array(
  'expires' => time() + 60*60*24*30,
  'path' => '/',
  'domain' => '.domain.com', // leading dot for compatibility or use subdomain
  'secure' => true, // or false
  'httponly' => false, // or false
  'samesite' => 'None' // None || Lax || Strict
);

setcookie('cors-cookie', 'my-site-cookie', $cookie_options);

If you have PHP 7.2 or lower (as Robert's answered below):

setcookie('key', 'value', time()+(7*24*3600), "/; SameSite=None; Secure");

If your host is already updated to PHP 7.3, you can use (thanks to Mahn's comment):

setcookie('cookieName', 'cookieValue', [
  'expires' => time()+(7*24*3600,
  'path' => '/',
  'domain' => 'domain.com',
  'samesite' => 'None',
  'secure' => true,
  'httponly' => true
]);

Another thing you can try to check the cookies, is to enable the flag below, which—in their own words—"will add console warning messages for every single cookie potentially affected by this change":

chrome://flags/#cookie-deprecation-messages

See the whole code at: https://github.com/GoogleChromeLabs/samesite-examples/blob/master/php.md, they have the code for same-site-cookies too.

Solution 2:

As the new feature comes, SameSite=None cookies must also be marked as Secure or they will be rejected.

One can find more information about the change on chromium updates and on this blog post

Note: not quite related directly to the question, but might be useful for others who landed here as it was my concern at first during development of my website:

if you are seeing the warning from question that lists some 3rd party sites (in my case it was google.com, huh) - that means they need to fix it and it's nothing to do with your site. Of course unless the warning mentions your site, in which case adding Secure should fix it.

Solution 3:

>= PHP 7.3

setcookie('key', 'value', ['samesite' => 'None', 'secure' => true]);

< PHP 7.3

exploit the path
setcookie('key', 'value', time()+(7*24*3600), "/; SameSite=None; Secure");

Emitting javascript

echo "<script>document.cookie('key=value; SameSite=None; Secure');</script>";