Sum one number to every element in a list (or array) in Python

Solution 1:

if you want to operate with list of numbers it is better to use NumPy arrays:

import numpy
a = [1, 1, 1 ,1, 1]
ar = numpy.array(a)
print ar + 2

gives

[3, 3, 3, 3, 3]

using List Comprehension:

>>> L = [1]*5
>>> [x+1 for x in L]
[2, 2, 2, 2, 2]
>>>

which roughly translates to using a for loop:

>>> newL = []
>>> for x in L:
...     newL+=[x+1]
... 
>>> newL
[2, 2, 2, 2, 2]

or using map:

>>> map(lambda x:x+1, L)
[2, 2, 2, 2, 2]
>>>

You can also use map:

a = [1, 1, 1, 1, 1]
b = 1
list(map(lambda x: x + b, a))

It gives:

[2, 2, 2, 2, 2]

try this. (I modified the example on the purpose of making it non trivial)

import operator
import numpy as np

n=10
a = list(range(n))
a1 = [1]*len(a)
an = np.array(a)

operator.add is almost more than two times faster

%timeit map(operator.add, a, a1)

than adding with numpy

%timeit an+1