Entity Framework Code First Date field creation

Try to use ColumnAttribute from System.ComponentModel.DataAnnotations (defined in EntityFramework.dll):

[Column(TypeName="Date")]
public DateTime ReportDate { get; set; }

The EF6 version of David Roth's answer is as follows:

public class DataTypePropertyAttributeConvention 
    : PrimitivePropertyAttributeConfigurationConvention<DataTypeAttribute>
{
    public override void Apply(ConventionPrimitivePropertyConfiguration configuration, 
        DataTypeAttribute attribute)
    {
        if (attribute.DataType == DataType.Date)
        {
            configuration.HasColumnType("Date");
        }
    }
}

Register this as before:

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
     base.OnModelCreating(modelBuilder);

     modelBuilder.Conventions.Add(new DataTypePropertyAttributeConvention());
}

This has the same outcome as Tyler Durden's approach, except that it's using an EF base class for the job.

I use following

[DataType(DataType.Time)]
public TimeSpan StartTime { get; set; }

[DataType(DataType.Time)]
public TimeSpan EndTime { get; set; }
    
[DataType(DataType.Date)]
[Column(TypeName = "Date")]
public DateTime StartDate { get; set; }

[DataType(DataType.Date)]
[Column(TypeName = "Date")]
public DateTime EndDate { get; set; }

With Entity Framework 6 & SQL Server Express 2012 - 11.0.2100.60 (X64).
It works perfectly and generates time/date column types in SQL server